Asmakan wrote:
logann2 wrote:
logann2 wrote:
Consider watching cars on the highway. Each car can either turn left (L), right (R), or go straight (S).
How many possible combinations are there where exactly 2 cars go in the same direction?
Source: Based off a questions in "Probability with Applications in Engineering, Science, and Technology" (Carlton, Devore)
Here's how I did it...
We have 3 spots. We can choose 2 of them to be the same. 3C2. Then that group can choose from 3 options for what they'll do. 3C1. The remaining spot can't repeat so it can only choose 1 of 2 options. 2C1.
Thus we have 3C2*3C1*2C1 which evaluates to 18.
I'm thinking of it this way: I have two cars because they will go to 1 direction I will consider them 1. Then they have 3 options they will take 1. 3C1. Why the answer as above ?
First::There are no mention of cars - it can be infinite number of cars.
But, we were given 3 direction, where the car can move.
Next, we need to find in how many ways cars can travel in exactly 2 direction i.e Left & Right , Left & Straight , Right & Straight
After u ve analysed the ques, now it's time to combine the possible ways.
STEP 1:We ve 3 direction (LEFT, RIGHT & STRAIGHT) but we need exactly 2 : So this can be found by 3C2 ways
STEP 2: Now we got 3 options to choose from Left & Right , Left & Straight , Right & Straight ; This can be found by 3C1 ( because we can only choose one option out of 3)
Step 3::Next we only have got one option left to choose from 2 i,e ( if we have selected LEFT & RIGHT - one direction is already chosen and we are left with only one option) This can be found : 2C1 ways
Now combine them, you will get the answer.