GreenlightTestPrep wrote:
If x4=5x−2x+8, then x2−12x+40= ?
A) 0
B) 4
C) 8
D) 12
E) 32
Given:
x4=5x−2x+8Cross multiply to get:
(x)(x+8)=4(5x−2)Expand to get:
x2+8x=20x−8Subtract
20x from both sides:
x2−12x=−8Add
8 to both sides:
x2−12x+8=0STOP! Do NOT try to solve this quadratic equation for xInstead, notice that we now know that
x2−12x+8=0.
Our goal is to find the value of the expression
x2−12x+40 Since
x2−12x+8 and
x2−12x+40 are similar, we can do the following...
Take:
x2−12x+8=0Add
32 to both sides to get:
x2−12x+40=32Perfect! We now know the value of
x2−12x+40 Answer: E
Cheers,
Brent