Asmakan wrote:
Machines A and B operate independently of each other.
The probability that machine A operates properly is 0.4
The probability that machine B operates properly is 0.3
Quantity A |
Quantity B |
The probability that exactly one machine operates properly |
0.54 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Due to the rights issue, I changed the question numbers and didn't mention the resource
If events A and B are independent, then P(A
and B) = P(A)
x P(B)
If P(machine A operates properly) = 0.4, then P(machine A does NOT operate properly) = 0.6
If P(machine B operates properly) = 0.3, then P(machine B does NOT operate properly) = 0.7
Want to determine:
P(exactly one machine operates properly)There are two ways in which
exactly one machine operates properly:
1) machine A operates properly AND machine B does NOT operate properly
OR
2) machine B operates properly AND machine A does NOT operate properly
Let's calculate each probability
1) machine A operates properly AND machine B does NOT operate properlyP(machine A operates properly
AND machine B does NOT operate properly) = P(machine A operates properly)
x P(machine B does NOT operate properly)
= 0.4
x 0.7
=
0.282) machine B operates properly AND machine A does NOT operate properlyP(machine B operates properly
AND machine A does NOT operate properly) = P(machine B operates properly)
x P(machine A does NOT operate properly)
= 0.3
x 0.6
=
0.18So,
P(exactly one machine operates properly) =
0.28 +
0.18=
0.46We get:
QUANTITY A:
0.46QUANTITY B: 0.54
Answer: B
Cheers,
Brent