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A square with an area equal to 256 has its center at the

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chrish10
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A square with an area equal to 256 has its center at the [#permalink] New post   Updated on: 23 Nov 2019, 17:23
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A square with an area equal to 256 has its center at the origin, (0,0), in the xy-coordinate plane. The graph of a function f is defined by f(x)=cx3, for some positive constant c, intersects the square at two opposite vertices of the square. What is the value of C? (Enter your answer as a fraction?)


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Originally posted by chrish10 on 04 Oct 2019, 17:26.
Last edited by Carcass on 23 Nov 2019, 17:23, edited 1 time in total.
Edited by Carcass
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   05 Oct 2019, 13:01
1/64
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   06 Oct 2019, 01:56
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Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   19 Nov 2019, 08:25
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gagangm wrote:
Can anyone tell me? What does it mean by intersects the square at two opposite vertices of the square?


Here's an example of a curve (in red) intersecting two opposite vertices of a square:
Image

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Re: A square with an area equal to 256 has its center at the [#permalink] New post   19 Nov 2019, 08:26
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Picasso :-D
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mouda
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   23 Nov 2019, 17:17
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64



how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   20 Jan 2020, 05:11
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mouda wrote:
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64



how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?


Hope the image helps


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prototypevenom
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   20 Feb 2020, 20:21
RSQUANT wrote:
mouda wrote:
luffy wrote:
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64



how do you know that the possible intersections points are (8,8) or (-8,-8)?
Why not other pairs (4,4), (-4,-4)?


Hope the image helps




so it can be (-8,8) and (8,-8) too?
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Albs
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   07 Mar 2020, 15:39
@prototypevenom correct I used those coordinates and got the same answer
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Re: A square with an area equal to 256 has its center at the [#permalink] New post   20 Jul 2023, 10:34
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Re: A square with an area equal to 256 has its center at the [#permalink]
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