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A square with an area equal to 256 has its center at the
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Updated on: 23 Nov 2019, 17:23
Updated on: 23 Nov 2019, 17:23
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Question Stats:
68% (39:08) correct
32% (02:49) wrong based on 50 sessions
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A square with an area equal to 256 has its center at the origin, (0,0), in the xy-coordinate plane. The graph of a function f is defined by \(f(x)=cx^3\), for some positive constant c, intersects the square at two opposite vertices of the square. What is the value of C? (Enter your answer as a fraction?)
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\(\frac{1}{64}\)
Re: A square with an area equal to 256 has its center at the
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06 Oct 2019, 01:56
06 Oct 2019, 01:56
2
Possible intersections points: (8,8) or (-8,-8)
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
So given x=8, y=8 and for function f(x=8) = c*8*8*8
c*8*8*8 = 8
=> c = 1/64
