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A computer manufacturer builds 1,000 computers and all of th
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20 Jan 2020, 06:51
20 Jan 2020, 06:51
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Question Stats:
28% (00:52) correct
72% (01:32) wrong based on 50 sessions
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A computer manufacturer builds 1,000 computers and all of them are sold at a retail store for the same price. The total profit from all of the computer sales is $20,000, or 40% of the total cost of production for all the computers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The cost of one computer at a retail store |
$50 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Re: A computer manufacturer builds 1,000 computers and all of th
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20 Jan 2020, 07:56
20 Jan 2020, 07:56
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Carcass wrote:
A computer manufacturer builds 1,000 computers and all of them are sold at a retail store for the same price. The total profit from all of the computer sales is $20,000, or 40% of the total cost of production for all the computers.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
The cost of one computer at a retail store |
$50 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
One side question: If I understand this question correctly, then we can calculate the production cost of one computer from the information given, can't we?
Re: A computer manufacturer builds 1,000 computers and all of th
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20 Jan 2020, 08:09
20 Jan 2020, 08:09
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Expert Reply
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.
If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve
\(20,000=0.4x \)
\(x = 50,000
\)
if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.
So \(\frac{70,000}{1,000 }= 70\)
One computer costs 70 dollars
A is greater
Hope this helps
If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve
\(20,000=0.4x \)
\(x = 50,000
\)
if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.
So \(\frac{70,000}{1,000 }= 70\)
One computer costs 70 dollars
A is greater
Hope this helps
