Last visit was: 23 Nov 2024, 10:02 It is currently 23 Nov 2024, 10:02

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Verbal Expert
Joined: 18 Apr 2015
Posts: 30010
Own Kudos [?]: 36363 [2]
Given Kudos: 25927
Send PM
User avatar
Retired Moderator
Joined: 03 Dec 2019
Posts: 348
Own Kudos [?]: 956 [2]
Given Kudos: 0
Verbal Expert
Joined: 18 Apr 2015
Posts: 30010
Own Kudos [?]: 36363 [0]
Given Kudos: 25927
Send PM
User avatar
Retired Moderator
Joined: 03 Dec 2019
Posts: 348
Own Kudos [?]: 956 [0]
Given Kudos: 0
Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.
Verbal Expert
Joined: 18 Apr 2015
Posts: 30010
Own Kudos [?]: 36363 [0]
Given Kudos: 25927
Send PM
Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
Expert Reply
theBrahmaTiger wrote:
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.


yes. Correct
User avatar
GRE Prep Club Legend
GRE Prep Club Legend
Joined: 07 Jan 2021
Posts: 5042
Own Kudos [?]: 74 [0]
Given Kudos: 0
Send PM
Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Prep Club for GRE Bot
Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne