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A computer manufacturer builds 1,000 computers and all of th

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Carcass
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A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   20 Jan 2020, 06:51
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A computer manufacturer builds 1,000 computers and all of them are sold at a retail store for the same price. The total profit from all of the computer sales is $20,000, or 40% of the total cost of production for all the computers.

Quantity A
Quantity B
The cost of one computer at a retail store
$50



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

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theBrahmaTiger
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   20 Jan 2020, 07:56
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Carcass wrote:
A computer manufacturer builds 1,000 computers and all of them are sold at a retail store for the same price. The total profit from all of the computer sales is $20,000, or 40% of the total cost of production for all the computers.

Quantity A
Quantity B
The cost of one computer at a retail store
$50



A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.

Kudos for the right answer and explanation


One side question: If I understand this question correctly, then we can calculate the production cost of one computer from the information given, can't we?
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   20 Jan 2020, 08:09
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I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps
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theBrahmaTiger
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   20 Jan 2020, 08:16
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   20 Jan 2020, 08:36
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theBrahmaTiger wrote:
Carcass wrote:
I am not sure if I understood your question. However, we can figure out what the question is asking for: the cost of ONE computer.

If the profit (which is the Revenue minus the costs for the computer) is 20,000 and it is 40% of the costs we can solve

\(20,000=0.4x \)

\(x = 50,000
\)

if the profit are 20,000 and the costs are 50,000 the total operation at the retail level amount to 70,000.

So \(\frac{70,000}{1,000 }= 70\)

One computer costs 70 dollars

A is greater


Hope this helps


I was just wondering if $50 would be the production cost of one unit. I guess it is correct.


yes. Correct
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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink] New post   04 May 2023, 05:25
Hello from the GRE Prep Club BumpBot!

Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Re: A computer manufacturer builds 1,000 computers and all of th [#permalink]
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