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Mark has a bag full of red and blue marbles. For every 7 red
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22 Jan 2020, 00:47
22 Jan 2020, 00:47
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Question Stats:
80% (01:06) correct
20% (00:00) wrong based on 10 sessions
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Mark has a bag full of red and blue marbles. For every 7 red marbles in the bag, there are 5 blue marbles. Mark removes half of the red marbles from the bag. What fraction of the marbles does Mark remove from the bag?
A. 724
B. 220
C. 1448
D. 720
E. 1320
A. 724
B. 220
C. 1448
D. 720
E. 1320
Re: Mark has a bag full of red and blue marbles. For every 7 red
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22 Jan 2020, 02:04
22 Jan 2020, 02:04
1
According to the question,
Red marbles = 7k
Blue marbles = 5k
Total marbles = 12k
If half of the red marbles are removed then fraction of the marbles removed = 3.5k12k
It is hard to cut the marbles in half so k will take an even value.
if k = 2 then 3.5k12k=724
if k = 4 then 3.5k12k=1448=724 in the lowest form.
OA,A
Red marbles = 7k
Blue marbles = 5k
Total marbles = 12k
If half of the red marbles are removed then fraction of the marbles removed = 3.5k12k
It is hard to cut the marbles in half so k will take an even value.
if k = 2 then 3.5k12k=724
if k = 4 then 3.5k12k=1448=724 in the lowest form.
OA,A
huda wrote:
Mark has a bag full of red and blue marbles. For every 7 red marbles in the bag, there are 5 blue marbles. Mark removes half of the red marbles from the bag. What fraction of the marbles does Mark remove from the bag?
A. 724
B. 220
C. 1448
D. 720
E. 1320
A. 724
B. 220
C. 1448
D. 720
E. 1320
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Re: Mark has a bag full of red and blue marbles. For every 7 red
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23 Jan 2020, 01:23
23 Jan 2020, 01:23
1
Question)
Mark has a bag full of red and blue marbles. For every 7 red marbles in the bag, there are 5 blue marbles. Mark removes half of the red marbles from the bag. What fraction of the marbles does Mark remove from the bag?
Solution:
For every 7 red marbles in the bag, there are 5 blue marbles
=> Ratio of number of red marbles to number of blue marbles = 7 : 5
Let the number of red and blue marbles be 14k and 10k (we take an even number since we need to take half the number of red marbles)
[Note: We can multiply a ratio with any number keeping it unchanged. Observe that since the ratio has to be 7 : 5, 14k : 10k also equals 7 : 5]
Thus, total number of marbles = 24k
Number of marbles removed by Mark = 1/2 * 14k = 7k
=> Required fraction of total marbles that Mark removed = 7k/24k = 7/24
Answer A
Mark has a bag full of red and blue marbles. For every 7 red marbles in the bag, there are 5 blue marbles. Mark removes half of the red marbles from the bag. What fraction of the marbles does Mark remove from the bag?
Solution:
For every 7 red marbles in the bag, there are 5 blue marbles
=> Ratio of number of red marbles to number of blue marbles = 7 : 5
Let the number of red and blue marbles be 14k and 10k (we take an even number since we need to take half the number of red marbles)
[Note: We can multiply a ratio with any number keeping it unchanged. Observe that since the ratio has to be 7 : 5, 14k : 10k also equals 7 : 5]
Thus, total number of marbles = 24k
Number of marbles removed by Mark = 1/2 * 14k = 7k
=> Required fraction of total marbles that Mark removed = 7k/24k = 7/24
Answer A
