According to the question,
Red marbles = 7k
Blue marbles = 5k
Total marbles = 12k
If half of the red marbles are removed then fraction of the marbles removed = \(\frac{3.5k}{12k}\)
It is hard to cut the marbles in half so k will take an even value.
if k = 2 then \(\frac{3.5k}{12k} = \frac{7}{24}\)
if k = 4 then \(\frac{3.5k}{12k} = \frac{14}{48} = \frac{7}{24} \) in the lowest form.
OA,Ahuda wrote:
Mark has a bag full of red and blue marbles. For every 7 red marbles in the bag, there are 5 blue marbles. Mark removes half of the red marbles from the bag. What fraction of the marbles does Mark remove from the bag?
A. \(\frac{7}{24}\)
B. \(\frac{2}{20}\)
C. \(\frac{14}{48}\)
D. \(\frac{7}{20}\)
E. \(\frac{13}{20}\)