Carcass wrote:
If mx+qy−nx−py=0, p−q=2, and yx=−13 , then which of the following is true?
A. n−m=23
B. n−m=−23
C. m+n=23
D. m+n=32
E. m+n=−32
Tricky!!!
First notice that we can perform some factoring
in partsWe'll start by rearranging the terms to get some like terms together.
Take:
mx+qy−nx−py=0Rearrange to get:
mx−nx+qy−py=0Factor in parts to get:
x(m−n)+y(q−p)=0Now subtract
y(q−p) from both sides to get:
x(m−n)=−y(q−p)Rewrite the right side of the equation as follows:
x(m−n)=y(−q+p)Simplify to get:
x(m−n)=y(p−q)Divide both sides by
x to get:
m−n=y(p−q)xRewrite the right side of the equation to get:
m−n=yx(p−q)Replace
p−q, and
yx to get:
m−n=−13(2)Simplify to get:
m−n=−23Multiply both sides by
−1 to get:
−m+n=23Finally, rewrite as follows:
n−m=23Answer: A
Cheers,
Brent