Asif123 wrote:
An inlet pipe can fill an empty pool with water in 3 hours, and the pool’s outlet pipe can empty a full pool in 4 hours. The water flows at constant rates through both pipes regardless of the water level in the pool. If both pipes were inadvertently left open, what fraction of the pool would be filled exactly 2 hours after water began to flow into the empty pool?
(A) 1/12
(B) 1/6
(C) 1/4
(D) 1/3
(E) 1/2
Here,
** Total work = Rate * TimeRate of water filled in empty tank = \(\frac{1}{3}\)
Rate of water emptied from the tank = \(\frac{1}{4}\)
Total work done, when both pipes were left open for exactly 2 hours = \((\frac{1}{3} - \frac{1}{4}) * 2 = \frac{1}{6}\)
***PLZ mention the source