GeminiHeat wrote:
If \((z-3)^2 = 12\),then \(2z(z-6)=\)
A. 6
B. 9
C. 10
D. 15
E. 27
There are two possible approaches here:
1) Solve the original equation for z, and then plug that value into \(2z(z-6)\)
2) Take the original equation, \((z-3)^2 = 12\), and manipulate it so that it looks like \(2z(z-6)\)
Let's go with approach #2
Given: \((z-3)^2 = 12\)
Expand and simplify the left side: \(z^2-6z+9=12\)
Multiply both sides of the equation by 2 to get: \(2z^2-12z+18=24\)
Subtract 18 from both sides to get: \(2z^2-12z=6\)
Back to the left side: \(2z(z-6)=6\)
Answer: A
Cheers,
Brent