Carcass wrote:
A sports league encourages collaboration by awarding 3 points for each goal scored without assistance and 5 points for each goal scored with assistance. A total of 48 points were scored by a team in a single game. Which of the following CANNOT be the number of goals scored without assistance by this team in this game?
A. 1
B. 6
C. 11
D. 12
E. 16
Kudos for the right answer and explanation
Let the goals scored by Assistance be \(A\) and Without Assistance be \(W\)
Now, \(3W + 5A = 48\)
\(W = \frac{48 - 5A}{3}\)
\(W = 16 - \frac{5A}{3}\)
NOTE: \(A\) must be a multiple of \(3\)Let's check the options (Hit & Trial):
A. \(W = 1\) when \(A = 9\)B. \(W = 6\) when \(A = 6\)C. \(W = 11\) when \(A = 3\)D. \(W = 12\) when \(A = 2.4\)E. \(W = 16\) when \(A = 0\)Hence, option D