GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If (x+2)(x-5)/(x-3)(x+4)=1, then x=
[#permalink]
24 Feb 2020, 14:51
24 Feb 2020, 14:51
1
Expert Reply
00:00
Question Stats:
84% (01:08) correct
15% (01:56) wrong based on 32 sessions
Hide Show timer Statistics
If \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\), then \(x=\)
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If (x+2)(x-5)/(x-3)(x+4)=1, then x=
[#permalink]
25 Feb 2020, 07:33
25 Feb 2020, 07:33
2
Carcass wrote:
If \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\), then \(x=\)
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
A. \(-2\)
B. \(- \frac{1}{2}\)
C. \(1\)
D. \(\frac{1}{2}\)
E. \(2\)
Kudos for the right answer and explanation
Take: \(\frac{(x+2)(x-5)}{(x-3)(x+4)}=1\)
Multiply both sides of the equation by \((x-3)(x+4)\) to get: \((x+2)(x-5)=(x-3)(x+4)\)
Expand and simplify both sides to get: \(x^2-3x-10=x^2+x-12\)
Subtract \(x^2\) from both sides to get: \(-3x-10=x-12\)
Add 12 to both sides to get: \(-3x+2=x\)
Add \(3x\) to both sides to get: \(2=4x\)
Solve: \(x = \frac{2}{4}=\frac{1}{2}\)
Answer: D
Cheers,
Brent
Re: If (x+2)(x-5)/(x-3)(x+4)=1, then x=
[#permalink]
28 Jan 2024, 15:04
28 Jan 2024, 15:04
Hello from the GRE Prep Club BumpBot!
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
Thanks to another GRE Prep Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).
Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
