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Re: The sides of a parallelogram are 10 and 11... [#permalink]
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Hm3105 wrote:
The sides of a parallelogram are 10 and 11. The integral value of the length of the diagonal opposite to the acute angle is at most______

[spoiler=]OA: 14


We'll let the red star represent the acute angle in each case.
Notice that, as the acute angle approaches 90°, the length of the diagonal increases.
Image
So the greatest value of the length of the diagonal opposite the acute angle will occur when the acute angle is as close as possible to 90° (e.g., 89.99999999999999999°)

If the angle is 90°, then we can apply the Pythagorean theorem to see that that the length of the diagonal \(= \sqrt{221}\)
So, if the acute angle were 89.99999999999999999°, the length of the diagonal would be a teeny tiny bit less than \(\sqrt{221}\)

We already know that:
\(\sqrt{196}=14\)
and
\(\sqrt{225}=15\)

So, \(\sqrt{221}\) must be BETWEEN 14 and 15

Since the length of the diagonal must be an integer, the greatest possible length is 14

Answer: 14

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Re: The sides of a parallelogram are 10 and 11... [#permalink]
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Thank you Sir for the explanation provided.

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Re: The sides of a parallelogram are 10 and 11... [#permalink]
Awesome. Thanks for the beautiful answer! I thought it was going to take months for response. Much appreciated!
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Re: The sides of a parallelogram are 10 and 11... [#permalink]
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nerd77 wrote:
Awesome. Thanks for the beautiful answer! I thought it was going to take months for response. Much appreciated!


We reply as fast as we can. As much as we can.

A forum like this is not an easy task to handle. I know you are right.

However, once again, we try to reply to a student as fast as we can


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Re: The sides of a parallelogram are 10 and 11... [#permalink]
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Re: The sides of a parallelogram are 10 and 11... [#permalink]
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