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Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
When 34, 36, and 38 are each divided by positive integer d,
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13 Mar 2020, 08:53
13 Mar 2020, 08:53
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When 34, 36, and 38 are each divided by positive integer d, the remainders are 4, 0, and 2, respectively. When 41, 43, and 45 are each divided by positive integer k, the remainders are 5, 7, and 0, respectively. What is the value of d + k?
A) 12
B) 15
C) 18
D) 21
E) 24
A) 12
B) 15
C) 18
D) 21
E) 24
Re: When 34, 36, and 38 are each divided by positive integer d,
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14 Mar 2020, 19:55
14 Mar 2020, 19:55
1
34, 36, and 38 when each divided by positive integer d, leave the remainders are 4, 0, and 2 respectively.
This gives us a hint that d is a factor of 36. Now, since the divisor > remainder, d > 4.
Factors of 36 = 1,2,3,4,6,9,12,18,36.
Out of the values that are greater than 4, only 6 satisfies the condition.
\(d = 6\)
Similarly, When 41, 43, and 45 are each divided by positive integer k, the remainders are 5, 7, and 0, respectively.
This gives us a hint that k is a factor of 45. Now, since the divisor > remainder, k > 7.
Factors of 45 = 1,3,5,9,15,45.
Out of the values that are greater than 7, only 9 satisfies the condition.
\(k = 9\)
\( d+k = 6+9 = 15\)
OA,B
This gives us a hint that d is a factor of 36. Now, since the divisor > remainder, d > 4.
Factors of 36 = 1,2,3,4,6,9,12,18,36.
Out of the values that are greater than 4, only 6 satisfies the condition.
\(d = 6\)
Similarly, When 41, 43, and 45 are each divided by positive integer k, the remainders are 5, 7, and 0, respectively.
This gives us a hint that k is a factor of 45. Now, since the divisor > remainder, k > 7.
Factors of 45 = 1,3,5,9,15,45.
Out of the values that are greater than 7, only 9 satisfies the condition.
\(k = 9\)
\( d+k = 6+9 = 15\)
OA,B
GreenlightTestPrep wrote:
When 34, 36, and 38 are each divided by positive integer d, the remainders are 4, 0, and 2, respectively. When 41, 43, and 45 are each divided by positive integer k, the remainders are 5, 7, and 0, respectively. What is the value of d + k?
A) 12
B) 15
C) 18
D) 21
E) 24
A) 12
B) 15
C) 18
D) 21
E) 24
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: When 34, 36, and 38 are each divided by positive integer d,
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15 Mar 2020, 12:32
15 Mar 2020, 12:32
1
GreenlightTestPrep wrote:
When 34, 36, and 38 are each divided by positive integer d, the remainders are 4, 0, and 2, respectively. When 41, 43, and 45 are each divided by positive integer k, the remainders are 5, 7, and 0, respectively. What is the value of d + k?
A) 12
B) 15
C) 18
D) 21
E) 24
A) 12
B) 15
C) 18
D) 21
E) 24
----ASIDE----------------
When positive integer N is divided by positive integer D, the remainder R is such that 0 ≤ R < D
For example, if we divide some positive integer by 7, the remainder will be 6, 5, 4, 3, 2, 1, or 0
-----------------------------
If 34 divided by d leaves a reminder of 4, then (according to the above property), d > 4
If 36 divided by d leaves a reminder of 0, then d is a divisor of 36.
The divisors of 36 are: 1, 2, 3, 4, 6, 9, 12, 24 and 36
Since we already know that d > 4, d must be 6, 9, 12, 24 or 36. Let's test these five possible d-values
If d = 6, then 34, 36, and 38 divided by d leaves reminders 4, 0, and 2, respectively. PERFECT!!
At this point, we can stop examining other possible values of d (since the answer choices tell us there can be only one correct answer)
So d = 6
If 43 divided by k leaves a reminder of 7, then (according to the above property), k > 7
If 45 divided by k leaves a reminder of 0, then k is a divisor of 45.
The divisors of 45 are: 1, 3, 5, 9, 15 and 45
Since we already know that k > 7, k must be 9, 15 or 45. Let's test these three possible k-values
If k = 9, then 41, 43, and 45 divided by d leaves reminders 5, 7, and 0, respectively. PERFECT!!
So k = 9
What is the value of d + k?
d + k = 6 + 9 = 15
Answer: B
Cheers,
Brent
