Looks good to me.

Given that A fair six-sided die with faces numbered 1 through 6 is tossed 3 times and We need to find what is the probability of getting a 1 or a 2 on all three tosses?

As we are rolling a dice thrice => Number of cases = \(6^3\) = 216

We need to get a 1 or a 2 in all three rolls.

Probability of getting 1 or 2 in one roll = \(\frac{2}{6}\) (as there are two favorable outcomes 1 or 2 out of 6) = \(\frac{1}{3}\)

=> Probability of getting a 1 or a 2 on all three tosses = \(\frac{1}{3}\) * \(\frac{1}{3}\) * \(\frac{1}{3}\) = \(\frac{1}{27}\)

So, Answer will be \(\frac{1}{27}\)
Hope it helps!

Watch the following video to learn How to Solve Dice Rolling Probability Problems

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