Let the total work be 1 units.
Eugene completes W units in 4 hours, so in 1 hour, Eugene will complete \(\frac{1}{4}\) unit of work.
Similarly, Steve will complete \(\frac{1}{6}\) unit of work in 1 hour.
When Eugene and Steve work together, total work done in 1 hour = \(\frac{1}{4} + \frac{1}{6} = \frac{6+4}{24}\)
Work done together in 1 hour = \(\frac{10}{24} = \frac{5}{12}\)
Now \(\frac{5}{12}\) units of work is done in 1 hour.
Hours taken to complete 1 unit of work = \(\frac{1}{5/12} = \frac{12}{5} = 2 \frac{2}{5}\)
OA,CCarcass wrote:
If Eugene can complete a project in 4 hours and Steve can complete the same project in 6 hours, how many hours will it take Eugene and Steve to complete the project if they work together?
A. \(2\)
B. \(2 \frac{1}{4}\)
C. \(2 \frac{2}{5}\)
D. \(2 \frac{3}{4}\)
E. \(3\)
Kudos for the right answer and explanation