Carcass wrote:
The chance of rain in Dennyville is 40% on Monday and 80% on Tuesday. What is the probability that it rains in Dennyville on at least one of these two days?
A. 120%
B. 88%
C. 76%
D. 60%
E. 32%
Kudos for the right answer and explanation
We want P(at least one day of rain)
When it comes to probability questions involving "
at least," it's usually best to try using the
complement.
That is, P(Event A happening) = 1 - P(Event A
not happening)
So, here we get: P(at least one day of rain) = 1 -
P(not getting at least one day of rain)What does it mean to
not get at least one day of rain? It means getting zero rain.
So, we can write: P(getting at least one day of rain) = 1 -
P(getting zero days of rain)P(getting zero days of rain)P(getting zero days of rain) = P(no rain on Monday
AND no rain on Tuesday)
= P(no rain on Monday)
x P(no rain on Tuesday)
Given: P(rain on Monday) = 40% = 0.4, which means = P(NO rain on Monday) = 60% = 0.6
Given: P(rain on Tuesday) = 80% = 0.8, which means = P(NO rain on Tuesday) = 20% = 0.2
So, P(getting zero days of rain) = 0.6
x 0.2
=
0.12So, P(getting at least one day of rain) = 1 -
0.12= 0.88
= 88%
Answer: B
Cheers,
Brent