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If T is a set of 35 consecutive integers, of which 17 are ne
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07 Apr 2020, 03:45
07 Apr 2020, 03:45
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If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?
A. -2
B. -1
C. 0
D. 1
E. 2
Kudos for the right answer and explanation
A. -2
B. -1
C. 0
D. 1
E. 2
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If T is a set of 35 consecutive integers, of which 17 are ne
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07 Apr 2020, 05:06
07 Apr 2020, 05:06
1
Carcass wrote:
If T is a set of 35 consecutive integers, of which 17 are negative, what is the sum of all the integers in T ?
A. -2
B. -1
C. 0
D. 1
E. 2
Kudos for the right answer and explanation
A. -2
B. -1
C. 0
D. 1
E. 2
Kudos for the right answer and explanation
If 17 integers are negative, then the first 17 integers of the sum look like this: (-17) + (-16) + (-15) + .... (-4) + (-3) + (-2) + (-1)
35 - 17 = 18, so there are still 18 numbers to add to our sum
The next number in the sum is 0, which means the remaining 17 integers must all be positive.
So our sum looks like this: (-17) + (-16) + (-15) + .... (-4) + (-3) + (-2) + (-1) + (0) + 1 + 2 + 3 + . . . + 16 + 17
As we can see, for every NEGATIVE value, we have a POSITIVE value of the same magnitude.
For example we have -16 & 16, and -8 & 8, etc.
When we add each pair (consisting of a NEGATIVE value and the POSITIVE value of the same magnitude), we get 0
For example, (-16) + 16 = 0, and (-7) + 7 = 0
When we do this, our sum reduces to the sum of a bunch of zeros: 0 + 0 + 0 + ..... + 0 + 0
Answer: C
Cheers,
Brent
gmatclubot
Re: If T is a set of 35 consecutive integers, of which 17 are ne [#permalink]
07 Apr 2020, 05:06
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