GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
A certain automotive dealer sells only cars and trucks, and
[#permalink]
17 Aug 2018, 17:04
17 Aug 2018, 17:04
1
Expert Reply
1
Bookmarks
00:00
Question Stats:
96% (00:37) correct
3% (00:23) wrong based on 62 sessions
Hide Show timer Statistics
A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
Re: A certain automotive dealer sells only cars and trucks, and
[#permalink]
11 Apr 2020, 20:11
11 Apr 2020, 20:11
sandy wrote:
A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
Since,there are 51 trucks available
and the automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 : 3
no. of cars available = 17 ( 1: 3 or 17 : 51 and so on....)
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: A certain automotive dealer sells only cars and trucks, and
[#permalink]
13 Sep 2021, 07:15
13 Sep 2021, 07:15
1
sandy wrote:
A certain automotive dealer sells only cars and trucks, and the ratio of cars to trucks on the lot is 1 to 3. If there are currently 51 trucks for sale, how many cars does the dealer have for sale?
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
(A) 17
(B) 34
(C) 68
(D) 153
(E) 204
We can solve this question using equivalent ratios
We'll set up the ratios in the form: # of cars/# of trucks
Let x = the number of cars the dealer has for sale
So we can write: x/51 = 1/3
Cross multiply: (3)(x) = (51)(1)
Simplify: 3x = 51
Solve: x = 51/3 = 17
Answer: A
RELATED VIDEO
