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Walking a constant pace on flat ground, a hiker can cover M
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16 Apr 2020, 09:03
16 Apr 2020, 09:03
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Question Stats:
86% (01:27) correct
13% (01:20) wrong based on 23 sessions
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Walking a constant pace on flat ground, a hiker can cover M miles in 5 hours. On another day, if she walks again at this same pace on flat ground, how many miles can she cover in (1 + M) hours?
A) \(\frac{M}{5} + \frac{1}{5}\)
B) 6
C) \(\frac{M}{5} + \frac{5}{M}\)
D) \(\frac{5M}{M+1}\)
E) \(\frac{M^2 + M}{5}\)
A) \(\frac{M}{5} + \frac{1}{5}\)
B) 6
C) \(\frac{M}{5} + \frac{5}{M}\)
D) \(\frac{5M}{M+1}\)
E) \(\frac{M^2 + M}{5}\)
Re: Walking a constant pace on flat ground, a hiker can cover M
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16 Apr 2020, 09:04
16 Apr 2020, 09:04
+1 kudos to all the posts containing proper explanations
Re: Walking a constant pace on flat ground, a hiker can cover M
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16 Apr 2020, 21:46
16 Apr 2020, 21:46
1
Method 1 :
Lets say on the first day, she travels 10 miles in 5 hours, (M = 10) and on the second day, she travels x miles in 11 hrs (1 + M = 1 + 10 = 11).
Thus, 10 miles in hours and x miles in 11 hours. On solving this, we get x = 22.
Substitute the value of M in the options and we see that option E gives us 22. Thus, E is correct.
Method 2:
On day 1, she travels M miles in 5 hours and on day two, she travels x miles in (1 + M) hours.
On cross multiplying, we get x = (M)(1+M)/5
X = M + M^2 / 5.
This is option E.
Lets say on the first day, she travels 10 miles in 5 hours, (M = 10) and on the second day, she travels x miles in 11 hrs (1 + M = 1 + 10 = 11).
Thus, 10 miles in hours and x miles in 11 hours. On solving this, we get x = 22.
Substitute the value of M in the options and we see that option E gives us 22. Thus, E is correct.
Method 2:
On day 1, she travels M miles in 5 hours and on day two, she travels x miles in (1 + M) hours.
On cross multiplying, we get x = (M)(1+M)/5
X = M + M^2 / 5.
This is option E.
