workout wrote:
Point A in the xy-coordinate system is shown below. Given two other points B (4a, b) and C (2a, 5b), what is the area of triangle ABC in terms of a and b?
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A) \(\frac{7ab}{2}\)
B) \(\frac{9ab}{2}\)
C) \(\frac{15ab}{2}\)
D) \(4ab\)
E) \(6ab\)
From the diagram, it is clear that:
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Area = 1/2 * Base * H = 1/2 * (4a - a) * (5b - b) = 6ab