GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
In the figure above, the circle is centered at (0, 0). What
[#permalink]
19 Jul 2019, 02:23
19 Jul 2019, 02:23
Expert Reply
00:00
Question Stats:
80% (01:27) correct
19% (02:08) wrong based on 41 sessions
Hide Show timer Statistics
Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png [ 16.34 KiB | Viewed 2546 times ]
In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8) (not shown on the graph)?
(A) 18
(B) 20
(C) 22
(D) 24
(E) 26
MyGuru Representative
Joined: 09 Apr 2020
Posts: 35
Given Kudos: 0
Re: In the figure above, the circle is centered at (0, 0). What
[#permalink]
26 Apr 2020, 19:04
26 Apr 2020, 19:04
1
Expert Reply
Carcass wrote:
Attachment:
#GREpracticequestion In the figure above, the circle is centered at.png
In the figure above, the circle is centered at (0, 0). What is the distance between point P and the point (–10, –8) (not shown on the graph)?
(A) 18
(B) 20
(C) 22
(D) 24
(E) 26
Since the center of the circle is at the origin, we can easily figure out that the radius is 16--meaning that the coordinates of point P are (0,16).
Now we just need to find the distance between (0,16) and the given point (-10,-8).
We can use the distance formula (really just the Pythagorean theorem):
\(\sqrt{(-8-16)^2+(-10-0)^2}\)
\(\sqrt{(-24)^2+(-10)^2}\)
\(\sqrt{676}\)=24
Answer: E
gmatclubot
Re: In the figure above, the circle is centered at (0, 0). What [#permalink]
26 Apr 2020, 19:04
Moderators:
