Carcass wrote:
A certain bag contains red balls, green balls, and blue balls and no other balls. The ratio of the number of red balls to the number of blue balls is 2:3, and the ratio of the number of blue balls to the number of green balls is 4:3. The number of blue balls in the bag is what fraction of the total number of balls in the bag?
A. \(\frac{3}{8}\)
B. \(\frac{12}{29}\)
C. \(\frac{7}{13}\)
D. \(\frac{15}{23}\)
E. \(\frac{12}{17}\)
Kudos for the right answer and explanation
Here,
Ratio of
RED : BLUE = 2 : 3Ratio of
BLUE : GREEN = 4 : 3 Now, we have to make the blue common :
R : B 2 : 3
8 : 12
B : G 4 : 3
12 : 9
or
R :B : G = 8 : 12 : 9Total nos. = 8 + 12 + 9 = 29
No. of blue balls = 12
Fraction of no. of blue balls to the total number of balls in the bag= \(\frac{12}{29}
\)