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Given that in the two names
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Updated on: 01 Sep 2016, 00:15
Updated on: 01 Sep 2016, 00:15
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Question Stats:
54% (01:21) correct
45% (01:20) wrong based on 42 sessions
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Given that in the two names JULLIE and LILLY, if one letter is picked from both simultaneously at random, then find the probability that the letters is same?
Is this GRE type question???
Show: ::
7/30
Is this GRE type question???
Originally posted by Sonalika42 on 30 Aug 2016, 02:39.
Last edited by Sonalika42 on 01 Sep 2016, 00:15, edited 3 times in total.
Last edited by Sonalika42 on 01 Sep 2016, 00:15, edited 3 times in total.
Re: Given that in the two names
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30 Aug 2016, 04:19
30 Aug 2016, 04:19
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Sonalika42 wrote:
Given that in the two names JULLIE and LILLY, if one letter is picked from both simultaneously at random, then find the probability that the letters is same?
Is this GRE type question???
Is this GRE type question???
The letters common in both names is L and I.
So the problem reduces to Probability of L from both the names and Probability of I from both names.
Let P1 be probabilities from Jullie and P2 be probabilities from Lilly
P1(L)= 2/6
P2(L)= 3/5
and
P1 (I)= 1/6
P2 (I)= 1/5
So probability of same letter being picked = P1(L)*P2(L) + P1(I)+P2(I)= \(\frac{2}{6}*\frac{3}{5}\)\(+\frac{1}{6}*\frac{1}{5}\)=\(\frac{7}{30}\)
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Re: Given that in the two names
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29 Mar 2019, 08:13
29 Mar 2019, 08:13
1
Sonalika42 wrote:
Given that in the two names JULLIE and LILLY, if one letter is picked from both simultaneously at random, then find the probability that the letters is same?
Is this GRE type question???
Show: ::
7/30
Is this GRE type question???
Yes, this could be a GRE question.
There are only two ways we can select the same two letters:
- Choose an L from JULLIE and choose an L from LILLY
- Choose an I from JULLIE and choose an I from LILLY
So, P(same letters) = P(choose L from JULLIE and L from LILLY OR choose I from JULLIE and I from LILLY)
= P(choose L from JULLIE and L from LILLY + P(choose I from JULLIE and I from LILLY)
= [P(choose L from JULLIE) x P(L from LILLY)] + [P(choose I from JULLIE) x P(I from LILLY)]
= (2/6 x 3/5) + (1/6 x 1/5)
= 6/30 + 1/30
= 7/30
Answer: 7/30
Cheers,
Brent
