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Re: In the figure above, STVW is a square. SX and YZ intersect a
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08 Oct 2020, 09:09
2
Correct Answer: b) 40 degrees
We know that STVW is a square. Let us assume that side of square is x => VW = x -------------->(1) We are given that UW = 2UV -------------------------> (2) Consider triangle UVW, Angle V is 90 degrees => UW^2 = UV^2 +VW^2 => From (2) and (1), (2UV)^2 = UV^2 +x^2 => 4UV^2 - UV^2 = x^2 => 3UV^2 = x^2 => UV = x/√3
Now, given that UW = 2UV = 2X/√3 Consider that UV:VW:UW = x/√3 : X : 2X/√3 = 1 : √3. : 2 => UVW is 30-60-90 triangle. => Angle VUW. = 60 Angle VWU = 30 This means that 3a = 30 = 90 => 3a = 60 => a =20
Since SX and YZ intersect at point W, Angle ZWS = Angle XWY => B = 2a => b= 40 degrees
Re: In the figure above, STVW is a square. SX and YZ intersect a
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07 May 2020, 21:45
3
We know that STVW is a square, thus all angles must be 90. Consider triangle UVW, we're given that UW is twice as long as UV. In case of 30-60-90 triangle only the hypotenous is twice the length of smaller side. Thus, angle VWU must be 30. Thus, 3a = 60, a = 20. We can see that YZ passes through a and b. Thus a+30+90+b = 180, 20+30+90+b = 180, b = 180-140, b=40. Thus, option B.
Re: In the figure above, STVW is a square. SX and YZ intersect a
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01 Aug 2024, 15:46
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Re: In the figure above, STVW is a square. SX and YZ intersect a [#permalink]