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A machine works at a constant rate and produces a bolts in 1
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14 May 2017, 05:06
14 May 2017, 05:06
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Question Stats:
51% (01:20) correct
48% (01:13) wrong based on 167 sessions
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A machine works at a constant rate and produces a bolts in 15 minutes and b bolts in c hours.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
b |
3ac |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Drill 1
Question: 12
Page: 339
Question: 12
Page: 339
Re: A machine works at a constant rate and produces a bolts in 1
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10 May 2020, 00:08
10 May 2020, 00:08
5
The machine produces 1 bolt (a) in 15 min. Thus, it produces 4 bolts (b) in 1 hour (c) (not in minutes).
Option A: 4
Option B: 3*1*1 = 3
So option A is greater.
After reading the comments I noticed that, many people are converting c from hours to minutes. That is not necessary to do here. Unless and until it is stated in the question that give your answer in bolts produced per minute, then only we need to convert. Since, in this question nothing like that is stated, just substitute the value of c and a as is.
Option A: 4
Option B: 3*1*1 = 3
So option A is greater.
After reading the comments I noticed that, many people are converting c from hours to minutes. That is not necessary to do here. Unless and until it is stated in the question that give your answer in bolts produced per minute, then only we need to convert. Since, in this question nothing like that is stated, just substitute the value of c and a as is.
General Discussion
Re: A machine works at a constant rate and produces a bolts in 1
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04 Jun 2017, 15:03
04 Jun 2017, 15:03
1
Expert Reply
Explanation
Plug in values.
If a = 5 and c = 1, then b = 20. In that situation Quantity A is larger; eliminate choices (B) and (C).
Plug In again to see if this is always the case. If a = 100 and c = 2, then b = 800.
Quantity A is still larger. There isn’t anything else you can try that would change the values, so choice A is the best answer.
Plug in values.
If a = 5 and c = 1, then b = 20. In that situation Quantity A is larger; eliminate choices (B) and (C).
Plug In again to see if this is always the case. If a = 100 and c = 2, then b = 800.
Quantity A is still larger. There isn’t anything else you can try that would change the values, so choice A is the best answer.
