GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
If a/b>c/d>1, which of the following could be true about the
[#permalink]
23 May 2020, 01:55
23 May 2020, 01:55
1
Expert Reply
6
Bookmarks
00:00
Question Stats:
33% (02:13) correct
66% (02:08) wrong based on 118 sessions
Hide Show timer Statistics
If \(\frac{a}{b}>\frac{c}{d}>1\), which of the following could be true about the reciprocals of a,b,and c ?
A. \(\frac{1}{a}>\frac{1}{b}>0>\frac{1}{c}>\frac{1}{d}\)
B. \(\frac{1}{b}>\frac{1}{a}>0>\frac{1}{c}>\frac{1}{d}\)
C. \(\frac{1}{b}>\frac{1}{a}>0>\frac{1}{d}>\frac{1}{c}\)
D. \(\frac{1}{c}>\frac{1}{a}>0>\frac{1}{b}>\frac{1}{d}\)
E. \(\frac{1}{d}>\frac{1}{c}>0>\frac{1}{b}>\frac{1}{a}\)
A. \(\frac{1}{a}>\frac{1}{b}>0>\frac{1}{c}>\frac{1}{d}\)
B. \(\frac{1}{b}>\frac{1}{a}>0>\frac{1}{c}>\frac{1}{d}\)
C. \(\frac{1}{b}>\frac{1}{a}>0>\frac{1}{d}>\frac{1}{c}\)
D. \(\frac{1}{c}>\frac{1}{a}>0>\frac{1}{b}>\frac{1}{d}\)
E. \(\frac{1}{d}>\frac{1}{c}>0>\frac{1}{b}>\frac{1}{a}\)
Re: If a/b>c/d>1, which of the following could be true about the
[#permalink]
23 May 2020, 23:15
23 May 2020, 23:15
1
After viewing the options, we can see that c & d must be negative (first three option where c & d are less than 0).
Thus, select numbers accordingly. Let a = 15, b = 3, c = -12, d = -6. This satisfies the first condition as well.
Now on calculating the reciprocals, we can see that option B is perfect fit.
Thus, select numbers accordingly. Let a = 15, b = 3, c = -12, d = -6. This satisfies the first condition as well.
Now on calculating the reciprocals, we can see that option B is perfect fit.
Re: If a/b>c/d>1, which of the following could be true about the
[#permalink]
19 Aug 2020, 08:27
19 Aug 2020, 08:27
1
I have another suggestion, building on what sukrut was saying it might be clearer.
We could proceed by elimination.
The quickest thing we can say is that D isn't possible because if it were true, c and d (or a and b) would be of different signs, the ratio cannot be >1. --> eliminate D.
Then we look at answer A.
if \(\frac{1}{a}\) and \(\frac{1}{b}\) are positive this means that a,b are positive. But if a,b are positive and \(\frac{1}{a} > \frac{1}{b}\) this means \(\frac{b}{a}>1\) which is a contradiction --> eliminate A.
Answer B isn't ruled out so far.
Answer C is similar to B, so to see which one applies, we can check whether it's possible to have that \(0> \frac{1}{d} > \frac{1}{c}\).
If it were the case we would have \(d,c <0\) and thus \(0>c>d\) which would mean that \(\frac{c}{d} <1\) (take 0 > c=-2 > d=-4 to convince yourself). --> eliminate C.
And similarly we can also eliminate E because b is the analogous of d and a the analogous of c in this last assertion so the argument above still works. --> eliminate E.
So B could work and we could plug in the numbers by sukrut to complete the answer.
We could proceed by elimination.
The quickest thing we can say is that D isn't possible because if it were true, c and d (or a and b) would be of different signs, the ratio cannot be >1. --> eliminate D.
Then we look at answer A.
if \(\frac{1}{a}\) and \(\frac{1}{b}\) are positive this means that a,b are positive. But if a,b are positive and \(\frac{1}{a} > \frac{1}{b}\) this means \(\frac{b}{a}>1\) which is a contradiction --> eliminate A.
Answer B isn't ruled out so far.
Answer C is similar to B, so to see which one applies, we can check whether it's possible to have that \(0> \frac{1}{d} > \frac{1}{c}\).
If it were the case we would have \(d,c <0\) and thus \(0>c>d\) which would mean that \(\frac{c}{d} <1\) (take 0 > c=-2 > d=-4 to convince yourself). --> eliminate C.
And similarly we can also eliminate E because b is the analogous of d and a the analogous of c in this last assertion so the argument above still works. --> eliminate E.
So B could work and we could plug in the numbers by sukrut to complete the answer.
