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A byciclist travels up the hill at 10 miles per hour

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A byciclist travels up the hill at 10 miles per hour [#permalink] New post   29 Jun 2020, 05:33
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A bicyclist travels up the hill at 10 miles per hour and returns down the same hill at 30 miles per hour. What is his/her average speed, in miles per hour, for the entire journey up and down the hill ?


A. 15

B. 17

C. 20

D. 22

E. 25
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Carcass
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Re: A byciclist travels up the hill at 10 miles per hour [#permalink] New post   29 Jun 2020, 05:33
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Re: A byciclist travels up the hill at 10 miles per hour [#permalink] New post   29 Jun 2020, 10:06
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Let the distance one way = D

Average Speed = \frac{Total Distance}{Total Time}

Time uphill = D10

Time downhill = D30

Total time = D10+D30=30D+10D30×10=40D300

Total Distance =D+D=2D

Average Speed = 2D/40D300=2D×30040=15

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Carcass wrote:
A bicyclist travels up the hill at 10 miles per hour and returns down the same hill at 30 miles per hour. What is his/her average speed, in miles per hour, for the entire journey up and down the hill ?


A. 15

B. 17

C. 20

D. 22

E. 25
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Re: A byciclist travels up the hill at 10 miles per hour [#permalink] New post   02 Jul 2020, 08:21
Assume the one way distance as 30 miles (as it gives integers when calculating the time taken for each trip):

Time Uphill: ( 30/10 ) = 3hrs.

Time Downhill ( 30/30 ) = 1 hr

Therefore, Avg. Speed = 30(uphill) + 30(Downhill) / ( 3 + 1 ) = 60/4 = 15
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Re: A byciclist travels up the hill at 10 miles per hour [#permalink]
02 Jul 2020, 08:21
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