It's a bad question for a two reasons.
First, we aren't told whether Sandy eats at the diner. All we know is that she brings 1, 2, or three people to the diner. This might seem like small potatoes, but the test-makers would never allow such ambiguity in a question.
Second (and more importantly), if answer choice A (45) is one of the official answers, then this means Sandy having a hamburger and her husband having kale is the SAME as Sandy having kale and her husband having a hamburger. Those two outcomes seem very different to me.
Quote:
Sandy has a husband and 2 children. She brings at least 1 member of her family to a diner for lunch every day. The diner offers 10 lunch specials. If no one orders the same thing, how many different orders can Sandy`s family make For lunch?
Indicate all possible values.
A 45
B 90
C 120
D 210
E 720
F 5,040