Last visit was: 22 Nov 2024, 06:30 It is currently 22 Nov 2024, 06:30

Close

GRE Prep Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GRE score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
avatar
Intern
Intern
Joined: 17 Feb 2020
Posts: 16
Own Kudos [?]: 67 [1]
Given Kudos: 0
Send PM
Most Helpful Community Reply
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [2]
Given Kudos: 136
Send PM
General Discussion
avatar
Intern
Intern
Joined: 09 Jan 2020
Posts: 20
Own Kudos [?]: 19 [0]
Given Kudos: 0
Send PM
Manager
Manager
Joined: 02 Sep 2019
Posts: 181
Own Kudos [?]: 144 [0]
Given Kudos: 94
Concentration: Finance
GRE 1: Q151 V148
GPA: 3.14
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
I got here 3<x<15. something went wrong here
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [0]
Given Kudos: 136
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
GR3A wrote:
I got here 3<x<15. something went wrong here



My bad!

When I multiplied -1 by -3, I somehow got -3 (instead of 3)

I've corrected my mistake above.

Kudos to both of you!!!!!
Thanks for the heads up!!!

Cheers,
Brent
avatar
Intern
Intern
Joined: 08 Apr 2020
Posts: 20
Own Kudos [?]: 35 [0]
Given Kudos: 0
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
Shouldn't it JUST be answer B?
For option x>-9
X can be less than -9 and fulfill the inequality
ex) if x=-9.5
Abs(-(-9.5/3)+3) = 0.1667 which is still less than 2
Verbal Expert
Joined: 18 Apr 2015
Posts: 30003
Own Kudos [?]: 36350 [0]
Given Kudos: 25927
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
Expert Reply
Waiting the expert
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Own Kudos [?]: 12196 [0]
Given Kudos: 136
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
7jdjones7 wrote:
Shouldn't it JUST be answer B?
For option x>-9
X can be less than -9 and fulfill the inequality
ex) if x=-9.5
Abs(-(-9.5/3)+3) = 0.1667 which is still less than 2


x = -9.5 is not a solution to the original inequality, |(-x/3) + 1| < 2

If x = -9.5, then -x = -(-9.5) = 9.5
So, we get: |(9.5/3) + 1| < 2, which evaluates to be: 6.1666 < 2

Cheers,
Brent
avatar
Intern
Intern
Joined: 08 Apr 2020
Posts: 20
Own Kudos [?]: 35 [1]
Given Kudos: 0
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
GreenlightTestPrep wrote:
7jdjones7 wrote:
Shouldn't it JUST be answer B?
For option x>-9
X can be less than -9 and fulfill the inequality
ex) if x=-9.5
Abs(-(-9.5/3)+3) = 0.1667 which is still less than 2


x = -9.5 is not a solution to the original inequality, |(-x/3) + 1| < 2

If x = -9.5, then -x = -(-9.5) = 9.5
So, we get: |(9.5/3) + 1| < 2, which evaluates to be: 6.1666 < 2

Cheers,
Brent


I Just realized I put the initial "-" sign outside of the parenthesis, my bad haha
Intern
Intern
Joined: 22 Nov 2020
Posts: 9
Own Kudos [?]: 6 [1]
Given Kudos: 4
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
1
none of the answer choices are correct, is it not? because we get 3<x<15 , neither of them falls under this region.
Retired Moderator
Joined: 02 Dec 2020
Posts: 1831
Own Kudos [?]: 2146 [2]
Given Kudos: 140
GRE 1: Q168 V157

GRE 2: Q167 V161
Send PM
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
2
Sir,

We are getting \(3 < x <15\) . We are asked which of the choices must be true.

Now \(x\) must be +ve hence \(x >0\) & \(x > -9\)

Please ask if the doubt remains.

AjitPatil wrote:
none of the answer choices are correct, is it not? because we get 3<x<15 , neither of them falls under this region.
Prep Club for GRE Bot
Re: If mod[(-x/3)+1]<2, which of the following. [#permalink]
Moderators:
GRE Instructor
84 posts
GRE Forum Moderator
37 posts
Moderator
1111 posts
GRE Instructor
234 posts

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne