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Fifteen candies are to be divided up among six children so
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20 Jul 2020, 05:08
20 Jul 2020, 05:08
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Question Stats:
79% (00:34) correct
20% (00:42) wrong based on 54 sessions
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Fifteen candies are to be divided up among six children so that each child receives at least two candies.
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
The probability that any child receives six candies |
0 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Re: Fifteen candies are to be divided up among six children so
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20 Jul 2020, 05:08
20 Jul 2020, 05:08
Expert Reply
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Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Question From Our New Project: GRE Quant Challenge Questions Daily - NEW EDITION!
Re: Fifteen candies are to be divided up among six children so
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27 Jul 2020, 23:34
27 Jul 2020, 23:34
Six children receive atleast 2 candles. 6*2 = 12 candles.
We are left with 15-12 = 3 candles. If all 3 are given to ONE child, the child still has max 5 candles.
Hence, probability of a child getting 6 candles = 0. C.
We are left with 15-12 = 3 candles. If all 3 are given to ONE child, the child still has max 5 candles.
Hence, probability of a child getting 6 candles = 0. C.
