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2/x = 2-x / x-2
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24 Jul 2020, 05:54
24 Jul 2020, 05:54
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\(\frac{2}{x} = \frac{2-x }{ x-2}\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
0 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
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Re: 2/x = 2-x / x-2
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24 Jul 2020, 06:26
24 Jul 2020, 06:26
1
Farina wrote:
\(\frac{2}{x} = \frac{2-x }{ x-2}\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
0 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Given: \(\frac{2}{x} = \frac{2-x }{ x-2}\)
Rewrite the right side as follows: \(\frac{2}{x} = \frac{-1(-2+x)}{x-2}\)
In other words: \(\frac{2}{x} = \frac{-1(x-2)}{x-2}\)
Simplify the right side to get: \(\frac{2}{x} = -1\)
From this we can conclude that \(x = -2\), which means Quantity B is greater.
Answer: B
Cheers,
Brent
Re: 2/x = 2-x / x-2
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24 Jul 2020, 06:33
24 Jul 2020, 06:33
GreenlightTestPrep wrote:
Farina wrote:
\(\frac{2}{x} = \frac{2-x }{ x-2}\)
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Quantity A |
Quantity B |
x |
0 |
A. Quantity A is greater.
B. Quantity B is greater.
C. The two quantities are equal.
D. The relationship cannot be determined from the information given.
Given: \(\frac{2}{x} = \frac{2-x }{ x-2}\)
Rewrite the right side as follows: \(\frac{2}{x} = \frac{-1(-2+x)}{x-2}\)
In other words: \(\frac{2}{x} = \frac{-1(x-2)}{x-2}\)
Simplify the right side to get: \(\frac{2}{x} = -1\)
From this we can conclude that \(x = -2\), which means Quantity B is greater.
Answer: B
Cheers,
Brent
Thanks, it was a great explanation
