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If y = 12x – 17, then the least integer x for which y is gre
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29 Jul 2020, 10:44
29 Jul 2020, 10:44
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If y = 12x – 17, then the least integer x for which y is greater than 100 is
A. 7
B. 8
C. 9
D. 10
E. 11
Kudos for the right answer and explanation
A. 7
B. 8
C. 9
D. 10
E. 11
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: If y = 12x – 17, then the least integer x for which y is gre
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29 Jul 2020, 11:09
29 Jul 2020, 11:09
1
Carcass wrote:
If y = 12x – 17, then the least integer x for which y is greater than 100 is
A. 7
B. 8
C. 9
D. 10
E. 11
Kudos for the right answer and explanation
A. 7
B. 8
C. 9
D. 10
E. 11
Kudos for the right answer and explanation
Given: y = 12x – 17
The least integer x for which y is greater than 100 is
So, we want: y > 100
Replace y with 12x – 17 to get: 12x – 17 > 100
Add 17 to both sides of the inequality to get: 12x > 117
Divide both sides by 12 to get: x > 117/12
No need to grab your calculator!
Since 108/12 = 9 and since 120/12 = 10, we know that 117/12 = 9.something
So we get: x > 9.something
Since x must be an INTEGER, the smallest possible value of x is 10
Answer: D
Cheers,
Brent
gmatclubot
Re: If y = 12x – 17, then the least integer x for which y is gre [#permalink]
29 Jul 2020, 11:09
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