Carcass wrote:
If y = 12x – 17, then the least integer x for which y is greater than 100 is
A. 7
B. 8
C. 9
D. 10
E. 11
Kudos for the right answer and explanation
Given:
y = 12x – 17The least integer x for which y is greater than 100 isSo, we want:
y > 100Replace
y with
12x – 17 to get:
12x – 17 > 100Add 17 to both sides of the inequality to get: 12x > 117
Divide both sides by 12 to get:
x > 117/12No need to grab your calculator!Since 108/12 = 9 and since 120/12 = 10, we know that
117/12 = 9.somethingSo we get:
x > 9.somethingSince x must be an INTEGER, the smallest possible value of x is 10
Answer: D
Cheers,
Brent