Carcass wrote:
For which of the following values of n is \(\frac{(100+n)}{n}\) NOT an integer?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 5
The GRE loves this nice identity:
\(\frac{a+b}{c} = \frac{a}{c} + \frac{b}{c}\)So, \(\frac{100+n}{n} = \frac{100}{n} + \frac{n}{n}\)
= \(\frac{100}{n} + 1\)
Since 1 is already an integer, we can see that 100/n + 1 will be an integer whenever 100/n is an integer.
In other words, 100/n + 1 is an integer whenever 100 is divisible by n.
Conversely, 100/n + 1 is NOT an integer whenever 100 is NOT divisible by n.
Since 100 is NOT divisible by 3, the correct answer is C