Carcass wrote:
List X: 28, 14, 63, 22, 53, 35
List Y (not shown) consists of 6 distinct numbers. Each number in list Y was obtained by dividing one of the numbers in list X by 7 and then subtracting 3 from the resulting number.
Quantity A |
Quantity B |
The range of the numbers in list Y |
6 |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Remind the following properties about Range.
\(Range(X) = Max(X) - Min(X)\)
\(Range(aX+b) = |a|Range(X)\)
We have \(Y = \frac{X}{7} - 3\) since each number in Y is obtained by dividing a number in \(X\) by \(7\) and then subtracting \(3\).
\(Range(X) = 63 - 14 = 49\).
\(Rante(Y) = Range(\frac{X}{7}-3) = (\frac{1}{7})Range(X) = (\frac{1}{7})49 = 7\).
Thus we have \(A = 7\), which is greater than \(B = 6\).
Therefore, A is the right answer.