dazedandconfused wrote:
What I am confused by is the fact that if we use the equation of a geometric series, we get the value of the tenth term to be 512∗(the original population). This is because we know that an=a1∗rn−1. Using this formula, given that r=2, an=a1∗210−1=512∗a1.
How is it that we cannot use the geometric series to find the 10th term in this setting?
If
a1 represents the INITIAL population, then
a2 represents the population after 1 "doubling"
So,
a2=a1∗21=a1∗(2)Likewise,
a3 represents the population after 2 "doublings"
So,
a3=a1∗22=a1∗(4)Likewise,
a4 represents the population after 3 "doublings"
So,
a4=a1∗23=a1∗(8)In general,
an represents the population after n-1 "doublings"
So,
an=a1∗rn−130/3 = 10
So, the population gets doubled 10 times.
Since
an represents the population after n-1 "doublings," we need to find the value of
a11We get:
a11=a1∗210=a1∗1024Cheers,
Brent