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GRE Math Challenge #143- The median of 10, 15, x, and y is 1
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15 May 2015, 11:44
15 May 2015, 11:44
Expert Reply
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Question Stats:
68% (00:58) correct
32% (01:10) wrong based on 50 sessions
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The median of 10, 15, x, and y is 18.5, and x<y.
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Quantity A |
Quantity B |
X |
22 |
• Quantity A is greater.
• Quantity B is greater.
• Both Quantities are Equal
• Cannot be determined
Re: GRE Math Challenge #143- The median of 10, 15, x, and y is 1
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09 Dec 2016, 02:20
09 Dec 2016, 02:20
1
Answer is D
Re: GRE Math Challenge #143- The median of 10, 15, x, and y is 1
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09 Dec 2016, 08:13
09 Dec 2016, 08:13
2
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The given set is 10 15 x and y and x is less than y.
Now clearly x > 15 otherwise the median of the set would be \(\frac{(10+15)}{2}\)=12.5
So the set is 10, 15, x and y. The median is \(\frac{(x+15)}{2}\)=18.5
so \(x+15=18.5*2\) or \(x=37-15 =22\).
The answer is C
Now clearly x > 15 otherwise the median of the set would be \(\frac{(10+15)}{2}\)=12.5
So the set is 10, 15, x and y. The median is \(\frac{(x+15)}{2}\)=18.5
so \(x+15=18.5*2\) or \(x=37-15 =22\).
The answer is C
