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In the figure above, if the area of the inscribed rectangula
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17 Dec 2016, 07:52
17 Dec 2016, 07:52
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82% (01:31) correct
17% (01:16) wrong based on 80 sessions
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#GREpracticequestion In the figure above, if the area of the inscribed.jpg [ 6.53 KiB | Viewed 3715 times ]
In the figure above, if the area of the inscribed rectangular region is 32, then the circumference of the circle is
(A) 20π
(B) 4π√5
(C) 4π√3
(D) 2π√5
(E) 2π√3
Re: In the figure above, if the area of the inscribed rectangula
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29 Sep 2017, 07:49
29 Sep 2017, 07:49
2
The area of the rectangular is x∗2x=32, from which we get x = 4 (we exclude x = -4 because a side of a rectangular cannot have a negative length.
Then, using Pitagora's theorem we can find the length of the hypotenuse of the triangle, which is half of the rectangular and we get it equal to √(80)=4sqrt(5).
Finally, the circumference of the circle is given by 2r∗π where 2r is the diameter that in this case equals 4sqrt(5).
Thus, the circumference is equal to 4π√(5). Answer B!
Then, using Pitagora's theorem we can find the length of the hypotenuse of the triangle, which is half of the rectangular and we get it equal to √(80)=4sqrt(5).
Finally, the circumference of the circle is given by 2r∗π where 2r is the diameter that in this case equals 4sqrt(5).
Thus, the circumference is equal to 4π√(5). Answer B!
Re: In the figure above, if the area of the inscribed rectangula
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01 Jan 2022, 22:43
01 Jan 2022, 22:43
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