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A car garage employs 3 mechanics. Three mechanics are able t
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01 Dec 2020, 09:08
01 Dec 2020, 09:08
Expert Reply
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Question Stats:
73% (01:21) correct
26% (02:49) wrong based on 26 sessions
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A car garage employs 3 mechanics. Three mechanics are able to fully service 6 cars in 4 hours. If the car garage doubled its number of mechanics, how long would it take for the garage to fully service 15 cars?
A. 5 hours
B. 4 hours
C. 6 hours
D. 6.5 hours
E. 8 hours
A. 5 hours
B. 4 hours
C. 6 hours
D. 6.5 hours
E. 8 hours
Re: A car garage employs 3 mechanics. Three mechanics are able t
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01 Dec 2020, 09:48
01 Dec 2020, 09:48
1
Let's start by setting up the equation: Work done = Amount of workers * rate * time
We are told that there are 3 mechanics that service 6 cars in 4 hours so set it up as such:
6 (cars serviced) = 3 (mechanics) * rate (we don't know the rate, we want to solve for it first) * 4 (hours)
Solving for rate yields 1/2. This rate is crucial because now we're going to essentially repeat this process BUT we use this rate to solve for another term that we don't have!
The question we need to answer: 'If the car garage doubled its number of mechanics how long would it take for the garage to fully service 15 cars?'
So let's use the first equation again and set it up now with this newly acquired information:
15 (15 cars need to be serviced) = 6 (remember, we double the number of mechanics, so from 3 --> 6) * 1/2 (this is the rate we previously calculated) * x (x is hours)
Solve this equation for x and we get 5 hours.
If anyone has any questions please ask.
We are told that there are 3 mechanics that service 6 cars in 4 hours so set it up as such:
6 (cars serviced) = 3 (mechanics) * rate (we don't know the rate, we want to solve for it first) * 4 (hours)
Solving for rate yields 1/2. This rate is crucial because now we're going to essentially repeat this process BUT we use this rate to solve for another term that we don't have!
The question we need to answer: 'If the car garage doubled its number of mechanics how long would it take for the garage to fully service 15 cars?'
So let's use the first equation again and set it up now with this newly acquired information:
15 (15 cars need to be serviced) = 6 (remember, we double the number of mechanics, so from 3 --> 6) * 1/2 (this is the rate we previously calculated) * x (x is hours)
Solve this equation for x and we get 5 hours.
If anyone has any questions please ask.
Re: A car garage employs 3 mechanics. Three mechanics are able t
[#permalink]
07 Dec 2020, 00:57
07 Dec 2020, 00:57
1
Given that the rate of 3 mechanics is 6/4.
If the number of mechanics is doubled, how long it take to service 15 cars?
6 mechanics at rate of "6/4 for each 3 mechanics" =6/4+6/4=15/x x=5
If the number of mechanics is doubled, how long it take to service 15 cars?
6 mechanics at rate of "6/4 for each 3 mechanics" =6/4+6/4=15/x x=5
