Carcass wrote:
If \(\frac{a}{b} = \frac{1}{3}\), \(\frac{b}{c} = 2\), \(\frac{c}{d} = \frac{1}{2}\), \(\frac{d}{e} = 3\) and \(\frac{e}{f} = \frac{1}{4}\), then what is the value of \(\frac{abc}{def}\) ?
(A) 27/4
(B) 27/8
(C) 3/4
(D) 3/8
(E) 1/4
Kudos for the right answer and explanation
Assign some values to the given variables.
Given: a/b = 1/3
Let a =
2 and b =
6 Given: b/c = 2
Since b =
6, it must be the case that c =
3 Given: c/d = 1/2
Since c =
3 , it must be the case that d =
6 Given: d/e=3
Since d =
6 , it must be the case that e =
2 Given: e/f = 1/4
Since e =
2 , it must be the case that f =
8 So, abc/def = (
2)(
6)(
3)/(
6)(
2)(
8)
= 36/96
= 3/8
Answer: D