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On a Monday in a certain restaurant, 20 percent of the 180 customers o
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18 Jan 2021, 09:23
18 Jan 2021, 09:23
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On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?
A. 15%
B. 16%
C. 18%
D. 23%
E. 30%
Kudos for the right answer and explanation
A. 15%
B. 16%
C. 18%
D. 23%
E. 30%
Kudos for the right answer and explanation
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o
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18 Jan 2021, 10:00
18 Jan 2021, 10:00
1
Carcass wrote:
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special. On Tuesday, only 10 percent of the 120 customers ordered the special. For the two days combined, what percent of the customers ordered the daily special?
A. 15%
B. 16%
C. 18%
D. 23%
E. 30%
Kudos for the right answer and explanation
A. 15%
B. 16%
C. 18%
D. 23%
E. 30%
Kudos for the right answer and explanation
On a Monday in a certain restaurant, 20 percent of the 180 customers ordered the daily special.
10% of 180 = 18
So, 20% of 180 = 36
So, 36 people ordered the daily special on MONDAY
On Tuesday, only 10 percent of the 120 customers ordered the special.
10% of 120 = 12
So, 12 people ordered the daily special on TUESDAY
For the two days combined, what percent of the customers ordered the daily special?
TOTAL number of people who ordered the daily special = 36 + 12 = 48 people
TOTAL number of customers for the two days = 180 + 120 = 300
So 48/300 of the customers ordered the special.
Our job is to rewrite 48/300 as a PERCENT. Here's one approach:
Take: 48/300
Divide top and bottom by 3 to get the EQUIVALENT fraction 16/100
16/100 = 16%
Answer: B
Cheers,
Brent
gmatclubot
Re: On a Monday in a certain restaurant, 20 percent of the 180 customers o [#permalink]
18 Jan 2021, 10:00
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