GRE Prep Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.
Customized
for You
Track
Your Progress
Practice
Pays
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
The figure above shows water in a tank whose base is 2 feet by 6 feet.
[#permalink]
Updated on: 21 Feb 2021, 10:02
Updated on: 21 Feb 2021, 10:02
Expert Reply
1
Bookmarks
00:00
Question Stats:
20% (02:15) correct
80% (01:20) wrong based on 10 sessions
Hide Show timer Statistics
Attachment:
GRE solid.jpg [ 25.41 KiB | Viewed 2908 times ]
The figure above shows water in a tank whose base is 2 feet by 6 feet. If a rectangular solid whose dimensions are 1 foot by 1 foot by 2 feet is totally immersed in the water, how many inches will the water rise?
(A) \(\frac{1}{6 }\)
(B) 1
(C) 2
(D) 3
(E) 12
Kudos for the right answer and explanation
The figure above shows water in a tank whose base is 2 feet by 6 feet.
[#permalink]
01 Feb 2021, 03:41
01 Feb 2021, 03:41
2
Hi,
I had a hard time solving this one(took me 5 mins to solve)
So, what I did was as we only have 2 dimensions for the tank, I considered the third one i.e. the height to be h feet.
Thus the Volume of the tank=lbh= 2*6*h=12h
Now the area of the rectangular solid=2*1*1=2feet
Hence, when we immerse this solid in the tank it will take the area of 2 feet. And the water, which was filled in the 2 feet will be raised.
Thus we need to find the height of the tank when the volume is 2 feet and the other dimensions being 2 &6
v=lbh
2=2*6*h
h=\(\frac{1}{6}\) feet
Please note we need final value in inches and not in feet.
12 inches=1 feet
So, \(\frac{1}{6}\) feet is 2 inches.
IMO C
I had a hard time solving this one(took me 5 mins to solve)
So, what I did was as we only have 2 dimensions for the tank, I considered the third one i.e. the height to be h feet.
Thus the Volume of the tank=lbh= 2*6*h=12h
Now the area of the rectangular solid=2*1*1=2feet
Hence, when we immerse this solid in the tank it will take the area of 2 feet. And the water, which was filled in the 2 feet will be raised.
Thus we need to find the height of the tank when the volume is 2 feet and the other dimensions being 2 &6
v=lbh
2=2*6*h
h=\(\frac{1}{6}\) feet
Please note we need final value in inches and not in feet.
12 inches=1 feet
So, \(\frac{1}{6}\) feet is 2 inches.
IMO C
Retired Moderator
Joined: 10 Apr 2015
Posts: 6218
Given Kudos: 136
Re: The figure above shows water in a tank whose base is 2 feet by 6 feet.
[#permalink]
01 Feb 2021, 07:07
01 Feb 2021, 07:07
1
Carcass wrote:
Attachment:
GRE solid.jpg
The figure above shows water in a tank whose base is 2 feet by 6 feet. If a rectangular solid whose dimensions are 1 foot by 1 foot by 2 feet is totally immersed in the water, how many inches will the water rise?
(A) \(\frac{1}{6 }\)
(B) 1
(C) 2
(D) 3
(E) 12
Kudos for the right answer and explanation
To begin, let's say that the tank (with base dimensions of 2 feet by 6 feet) is EMPTY
Volume of rectangular solid = (length)(width)(height) = (1)(1)(2) = 2 cubic feet
Now "melt" the rectangular solid and pour it into the original tank.
Our goal is to find the height of this "liquid" in the tank
Let h = the height of the liquid in the tank
Since the volume must be preserved, it must be the case that (length)(width)(height) = 2
Plug in our values to get: (2)(6)(h) = 2
Solve to get: h = 1/6
Answer: A
