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9<x<10
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10 Feb 2021, 10:18
10 Feb 2021, 10:18
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Question Stats:
69% (00:34) correct
30% (00:26) wrong based on 36 sessions
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\(9<x<10\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(x^2\) |
\(99\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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9<x<10
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10 Feb 2021, 10:44
10 Feb 2021, 10:44
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Carcass wrote:
\(9<x<10\)
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Quantity A |
Quantity B |
\(x^2\) |
\(99\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
GIVEN: \(9<x<10\)
\(\sqrt{81}=9\)
\(\sqrt{100}=10\)
So, we can rewrite the given information as follows:
GIVEN: \(\sqrt{81}<x<\sqrt{100}\)
So, it could be the case that \(x = \sqrt{82}\), in which case \(x^2 = 82\), which means Quantity B is greater
It could also be the case that \(x = \sqrt{99}\), in which case \(x^2 = 99\), which means the two quantities are equal
It could also be the case that \(x = \sqrt{99.5}\), in which case \(x^2 = 99.5\), which means Quantity A is greater
Answer: D
Re: 9<x<10
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11 Feb 2021, 00:25
11 Feb 2021, 00:25
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here we can use some numbers for x.
if x= 9.1
(A) x^2= 82
(B) 99
B here is bigger
and if x=9.99
(A)X^2= 99.8
(B) 99
A is bigger
answer is D
if x= 9.1
(A) x^2= 82
(B) 99
B here is bigger
and if x=9.99
(A)X^2= 99.8
(B) 99
A is bigger
answer is D
