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sqrt 25* sqrt 4 / sqrt 10
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10 Feb 2021, 10:04
10 Feb 2021, 10:04
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Question Stats:
68% (00:43) correct
31% (00:48) wrong based on 16 sessions
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Quantity A |
Quantity B |
\(\frac{ \sqrt{25} \times \sqrt{4}}{\sqrt{10}}\) |
\(3.5\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
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Re: sqrt 25* sqrt 4 / sqrt 10
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11 Feb 2021, 02:14
11 Feb 2021, 02:14
Carcass wrote:
Quantity A |
Quantity B |
\(\frac{ \sqrt{25} \times \sqrt{4}}{\sqrt{10}}\) |
\(3.5\) |
A)The quantity in Column A is greater.
B)The quantity in Column B is greater.
C)The two quantities are equal.
D)The relationship cannot be determined from the information given.
Kudos for the right answer and explanation
Lets try to do this question without calculator!
Col. A: \(\frac{\sqrt{100}}{\sqrt{10}}\) = \(\sqrt{10}\)
Col. B: 3.5
Squaring both sides;
Col. A: 10
Col. B: \(\frac{35}{10}\) x \(\frac{35}{10}\) = \(\frac{7}{2}\) x \(\frac{7}{2}\) = \(\frac{49}{4}\)
Multiply both sides with 4;
Col. A: 40
Col. B: 49
Since, A < B
Hence, option B
gmatclubot
Re: sqrt 25* sqrt 4 / sqrt 10 [#permalink]
11 Feb 2021, 02:14
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