KarunMendiratta wrote:
Mugdho wrote:
What is the total number of ways in which Dishu can distribute 9 distinct gifts among his 8 distinct girlfriends such that each of them gets at least one gift?
a)72*8!
b)144×8!
c)36*72*8!
d)12*7!*8
e)72*7!
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We have 9 gifts and 8 girls,
We can give these gifts to 8 different girls in 9! ways = 9 x 8 x 7 x 6 x 5 x 4 x 3 x 2
Since, 1 girl gets 2 gifts, We can select that girl as = \(^8C_1\) = 8
So, 8 x 9! = 8 x 9 x 8! = 72 x 8!
Hence, option A
KarunMendirattaWhat's wrong with the below Solution?
One among 8 gfs will get 2 gifts and remaining 7 will get one. So total of 9 gifts will be distributed among 8 gfs. i.e; 11111112
Gf who will get 2 gifts can be find out in 8C1 ways = 8 ways.
Now 2 gifts can be given to selected gf in 9C2 ways. And remaining 7 gifts can be given to remaining 7 gf in 7! ways.
So total no of ways= 8 × 9C2 × 7!
= 8×(9×8)2×7!
= 36 × 8 × 7!
= 36 × 8!