Carcass wrote:
Two cars started from the same point and traveled on a straight course in opposite directions for exactly three hours, at which time they were 330 miles apart. If one car traveled, on average, 10 miles per hour faster than the other car, what was the average speed of the slower car for the three-hour trip?
Let the speed of slower train be \(x\)
and that of faster train be \((x + 10)\)
Since, they are moving in
opposite direction, their
Relative speed = \((2x + 10)\)
Therefore,
\((2x + 10) = \frac{330}{3}\)
\((2x + 10) = 110\)
\(2x = 100\)
\(x = 50\)