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Re: Aaron’s first three quiz scores were 75, 84, and 82. If his [#permalink]
2
Arc29 wrote:
Answer is 55.
Since the sum of the first three is 241
Thus
241+x/3 = 74
which gives x=55

It should be 241+X/4=74

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Aaron’s first three quiz scores were 75, 84, and 82. If his [#permalink]
1
Scores = 75 , 84 , 82
Sum of scores = 75+84+82 = 241

Now it is given that after adding the fourth quiz score the average reduced to 74

Let's take score of 4th quiz = x

Average = 74 = \(\frac{241+x}{4}\)

x = 55

Rajdas wrote:
Arc29 wrote:
Answer is 55.
Since the sum of the first three is 241
Thus
241+x/3 = 74
which gives x=55

It should be 241+X/4=74

Posted from my mobile device
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Re: Aaron’s first three quiz scores were 75, 84, and 82. If his [#permalink]
1
The new average is 74.
therefore the mark scored in the last test- 75+84+82+X/ 4 =74

241+x/4= 74
x= (74*4)-241
x=55
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Re: Aaron’s first three quiz scores were 75, 84, and 82. If his [#permalink]
1
sandy wrote:
Aaron’s first three quiz scores were 75, 84, and 82. If his score on the fourth quiz reduced his average (arithmetic mean) quiz score to 74, what was his score on the fourth quiz?

Show: :: OA
55


Another Approach:

Since the average on 4 tests is 74
Let us see the difference between the overall average and each score

\(75 - 74 = 1\)
\(84 - 74 = 10\)
\(82 - 74 = 8\)

i.e. he has 19 surplus of 74, so we must subtract it from 74
\(74 - 19 = 55\)
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Re: Aaron’s first three quiz scores were 75, 84, and 82. If his [#permalink]
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